From 130392fa5c7c23aef6144c268004ca5cd5f9ca71 Mon Sep 17 00:00:00 2001
From: Alexei Ulanov <lucky-stees@yandex.ru>
Date: Fri, 9 Dec 2022 19:45:49 +0300
Subject: [PATCH] Fix the hostname for tiktok requests

---
 scraper.py | 2 +-
 1 file changed, 1 insertion(+), 1 deletion(-)

diff --git a/scraper.py b/scraper.py
index a24228b..225a987 100644
--- a/scraper.py
+++ b/scraper.py
@@ -309,7 +309,7 @@ class Scraper:
         print('正在获取TikTok视频数据...')
         try:
             # 构造访问链接/Construct the access link
-            api_url = f'https://api.tiktokv.com/aweme/v1/feed/?aweme_id={video_id}&iid=6165993682518218889&device_id={random.randint(10*10*10, 9*10**10)}&aid=1180'
+            api_url = f'https://api16-normal-c-useast1a.tiktokv.com/aweme/v1/feed/?aweme_id={video_id}&iid=6165993682518218889&device_id={random.randint(10*10*10, 9*10**10)}&aid=1180'
             print("正在获取视频数据API: {}".format(api_url))
             async with aiohttp.ClientSession() as session:
                 async with session.get(api_url, headers=self.tiktok_api_headers, proxy=self.proxies, timeout=10) as response: